Hello from MrBillDoesMath!
Answer:
(x+3)^2 -15 = 0
Discussion:
To complete the square add (and then subtract) the square of one-half the coefficient of x:
x^2 + 6x -6 = 0 =>
-- complete the square part --
x^2 + 6x + (6/2)^2 - (6/2)^2 - 6 = 0 =>
x^2 + 6x + 9 - 9 - 6 = 0 => as 6/2 = 3
(x + 3)^ 2 - 9 - 6 = 0 =>
(x+3)^2 -15 = 0
We can solve this as follows:
(x+3)^2 = 15 take square root of both sides
(x+3) = +\- sqrt(15)
x = -3 +\- sqrt(15)
Thank you,
MrB
