Question

How do you solve:
$x^{4} -8x^{3} + 24x^{2} -32x+16=0$

Answer 1

Answer:

x = 2

Step-by-step explanation:

Solve for x over the real numbers:

x^4 - 8 x^3 + 24 x^2 - 32 x + 16 = 0

Write the left hand side as a power:

(x - 2)^4 = 0

Take the 4^th root of both sides:

x - 2 = 0

Add 2 to both sides:

Answer:  x = 2