The diameter of each semicircular cross-section is given by the vertical distance between the curves [tex]y=e^{-x}[/tex] and [tex]y=0[/tex], which is just [tex]e^{-x}[/tex].
Given a semicircle with diameter [tex]d[/tex], its area is [tex]\dfrac{\pi d^2}8[/tex], so the area of each semicircular section is [tex]\dfrac{\pi e^{-2x}}8[/tex].
The volume of the solid is obtained by integrating from 0 to 1:
[tex]\displaystyle\frac\pi8\int_{x=0}^{x=1}e^{-2x}\,\mathrm dx=\frac{(e^2-1)\pi}{16e^2}[/tex]