As per condition of constant angular acceleration we can use kinematics
so here we will have
[tex]\theta = \omega_i t + \frac{1}{2}\alpha t^2[/tex]
here we know that
[tex]\theta = 5(2\pi) = 10\pi rad[/tex]
[tex]\omega_i = 2 rad/s[/tex]
t = 2 s
[tex]10\pi = 2(2) + \frac{1}{2}\alpha(2^2)[/tex]
[tex]\alpha = 13.7 rad/s^2[/tex]
so above is angular acceleration of the wheel