Question

How many grams of NaNO3 will precipitate if a saturated solution of NaNO3 in 200 g of water at 50°C is cooled to 20oC? Assume the following solubility values for NaNO3: 114.0g/100g H2O at 50oC; 88.0g/100g H2O at 20oC

Answer 1

Sodium nitrate is less soluble in cool water than warm. 144.0 grams are dissolved at 50°C, multiplying by 2 since there are 200 grams H2O = 72.0 grams. Then 88.0 grams are dissolved at 20°C, again multiplying by 2= 44.0 grams. Subtracting both we get the final value that 28.0 grams precipitate from the saturated solution.

Answer 2

52 grams of NaNO³ will precipitate if a saturated solution of NaNO3 in 200 g of water at 50 °C is cooled to 20 °C.

What is sodium nitrate?

Sodium nitrate is a preservative used to preserve meat, bacon, etc.

Given, 100g of water will dissolve 114.0 g of sodium nitrate at 50 °C and 88.0 g at 20 °C.

1 gram of water will dissolve 1.14 g of sodium nitrate and 0.88 g at 20 °C.

1.14 × 200 = 228 g of sodium nitrate at 50 °C 0.88 × 200 = 176 g at 20 °C.

Now subtract both quantities 228 – 176 = 52

Thus, the mass of $NaNO_3$ is 52 g.

Learn more about sodium nitrate

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