Respuesta :

Answer:

x≠-1,1

Step-by-step explanation:

f(g(x)) is a composition where g(x) is is substituted for x in f(x).

Recall, f(x) is 2/x. So we write 2/|x|-1. This places x in the denominator and 0 cannot be in the denominator x. Any value of x that makes the denominator 0 will not be in the domain.

|x|-1=0

|x|=1

x=1,-1


Bizzy6

Answer:

The domain of f (g (x)) is

x ≠ 1 and x ≠ -1

Step-by-step explanation:

We are given that

f(x) = 2/x      and

g(x) = lxl - 1

Let's plug g(x) into f(x)

f (g (x)) = 2 / (lxl - 1)

We know that we cannot have a denominator equal to zero, so we can set up an equality and solve

0 = lxl - 1

1 = lxl

Because x is an absolute value here

x = 1, x = -1

so x cannot equal either of these