Respuesta :
Answer:
x≠-1,1
Step-by-step explanation:
f(g(x)) is a composition where g(x) is is substituted for x in f(x).
Recall, f(x) is 2/x. So we write 2/|x|-1. This places x in the denominator and 0 cannot be in the denominator x. Any value of x that makes the denominator 0 will not be in the domain.
|x|-1=0
|x|=1
x=1,-1
Answer:
The domain of f (g (x)) is
x ≠ 1 and x ≠ -1
Step-by-step explanation:
We are given that
f(x) = 2/x and
g(x) = lxl - 1
Let's plug g(x) into f(x)
f (g (x)) = 2 / (lxl - 1)
We know that we cannot have a denominator equal to zero, so we can set up an equality and solve
0 = lxl - 1
1 = lxl
Because x is an absolute value here
x = 1, x = -1
so x cannot equal either of these