Question

The vertices of △ DEF are D (2, 5), E (6, 3), and F (4, 0). Translate △ DEF using the given vector. Graph △ DEF and its image. The vector is (6, 0). Please help!

Answer 1

Answer:

The image coordinates are D'(8, 5), E'(12, 3) and F'(10,0)

Step-by-step explanation:

Given the vertices of △ DEF are D (2, 5), E (6, 3), and F (4, 0). We have to translate the triangle using the vector (6, 0)

Now, translation by vector (6, 0)

D (2, 5)=D'(2+6, 5+0)=D'(8, 5)

E (6, 3)=E'(6+6, 3+0)=E'(12, 3)

F (4, 0)=F'(4+6, 0+0)=F'(10,0)

Now, we have to label the coordinate of the triangle or to get image of triangle after translation.

Hence, The image coordinates are D'(8, 5), E'(12, 3) and F'(10,0)

Answer 2

The resulting coordinate of △ D'E'F' is translated by the vector is (8, 5),  (12,3), and (10, 0)

Given the coordinates of vertices of △ DEF as D (2, 5), E (6, 3), and F (4, 0).

If the coordinate of the vertices is translated by the vector (6, 0), the resulting coordinates of △ D'E'F' will be expressed as:

D'= (2+6, 5 + 0) = (8, 5)

E' = (6 + 6, 3 + 0) = (12, 3)

F' = (4 + 6, 0 + 0) = (10, 0)

The graph of both triangles is as attached;

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