Question

A polynomial function P(x) with rational coefficients has the given roots find two additional roots of P(x)=0. 13+sqr root 3 and -7i

Answer 1

Answer:

13 - $\sqrt{3}$ and 7i

Step-by-step explanation:

complex roots occur in conjugate pairs as do radicals

Since 13 + $\sqrt{3}$ is a root then 13 - $\sqrt{3}$ is also a root

Since - 7i is a root then + 7i is also a root