This question is based on the graph. Therefore, the errors are:
(1) Error is that, three zeros (x-intercepts) does not make 3 peaks (vertices).
(2) Error is that, multiplying it by a negative is a reflection (not a steeper slope). Adding three on the outside of the factors is a vertical shift up (not a horizontal shift to the right).
(3) Error is that, multiplying by four makes a steeper slope (not a shallow slope).
Given:
Take a look at teen 1's initial polynomials for three layers of hills. Teen 1 has described what he thinks each modification to the initial polynomial will do.
According to the question,
Attachment of each curve, is below.
(1) I chose three points on the x-axis (the three zeros), and then I wrote each as a binomial to create the first polynomial. F(x) = (x – 1)(x – 3)(x – 4).
Answer: Error is that, three zeros (x-intercepts) does not make 3 peaks (vertices).
(2) Using the first polynomial as the base, I multiplied it by to flip it and make the hills steeper. Then, I added 3 to shift it to the right. F(x) =– (x – 1)(x – 3)(x – 4) + 3.
Answer: Error is that, multiplying it by a negative is a reflection (not a steeper slope). Adding three on the outside of the factors is a vertical shift up (not a horizontal shift to the right).
(3)This hill should be a shallow parabola that will rise up in the foreground of my picture. F(x) = 4(x–)(x – 5).
Answer: Error is that, multiplying by four makes a steeper slope (not a shallow slope).
Therefore, the errors are in each question,
(1) Error is that, three zeros (x-intercepts) does not make 3 peaks (vertices).
(2) Error is that, multiplying it by a negative is a reflection (not a steeper slope). Adding three on the outside of the factors is a vertical shift up (not a horizontal shift to the right).
(3) Error is that, multiplying by four makes a steeper slope (not a shallow slope).
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