Respuesta :
Answer:
Equation relating t and r is [tex]t = 2000 \frac{1}{r}[/tex] and constant of proportionality is 2000
Step-by-step explanation:
Given : the time, t(in minutes), you need to type a certain paper varies inversely with the rate, r(in words per minute), that you can type.
To Find: When typing 40 words per minute, you can finish in 50 minutes. find the constant of proportionality and write an equation relating t and r
Solution:
we are given that t(in minutes), you need to type a certain paper varies inversely with the rate, r(in words per minute), that you can type.
So, [tex]t \propto \frac{1}{r}[/tex]
[tex]\Rightarrow t = k \frac{1}{r}[/tex] ---1 Where k is the constant of proportionality
We are given that at r= 40 the value of t is 50
Substitute the values in 1
[tex]\Rightarrow 50 = k \frac{1}{40}[/tex]
[tex]\Rightarrow 50 \times 40 = k [/tex]
[tex]\Rightarrow 2000 = k [/tex]
Substitute the value of k in 1
[tex]\Rightarrow t = 2000 \frac{1}{r}[/tex]
Hence equation relating t and r is [tex]t = 2000 \frac{1}{r}[/tex] and constant of proportionality is 2000
Answer:t=2000/r
Step-by-step explanation: I also use acellus and that is the correct answer. i got this by knowing that k= equals the constant of proportionality. So taking that and the given, i would say 50=k/40. To get rid of the fraction, we multiply both sides by 40.