Respuesta :
Answer: h(0) = 100 , h(0) represents intial height
Step-by-step explanation:
h(t) = 100 - 16t²
h(0) = 100 - 16(0)²
= 100 - 0
= 100
h(0) represents the height at 0 seconds, which is the initial height
The height of the ball at [tex]0\;\rm seconds[/tex] is [tex]100\;\rm feets[/tex] as the ball was at the top of the building in the hand of the physics student.
According to the question, the given height function is [tex]h(t)=100-16t^2[/tex] where [tex]h[/tex] is the height of the building in feet and [tex]t[/tex] is the elapsed time in seconds.
Substitute [tex]t=0[/tex] in the height equation to determine the height of the ball at 0 second as-
[tex]h(0)=100-16(0)^2\\h(0)=100\;\rm feets[/tex]
Hence, the height of the ball at [tex]0\;\rm seconds[/tex] is [tex]100\;\rm feets[/tex] as the ball was at the top of the building in the hand of the physics student.
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