Respuesta :

Answer: (D) 7a⁴

Step-by-step explanation:

    [tex]\sqrt{49a^8}[/tex]

[tex]=\sqrt{49} \ \cdot \sqrt{a^8}[/tex]

[tex]=\sqrt{7\cdot 7} \ \cdot \sqrt{a\cdot a\cdot a\cdot a\cdot a\cdot a\cdot a\cdot a}[/tex]

Two on the inside of the radical (square root) symbol makes One on the outside.  Simplify by looking for pairs.

[tex]=\sqrt{\underline{7\cdot 7}} \ \cdot \sqrt{\underline{a\cdot a}\cdot \underline{a\cdot a}\cdot \underline{a\cdot a}\cdot \underline{a\cdot a}}[/tex]

= 7 · a · a · a · a

= 7a⁴

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