Question

m<KGH=x+161,m<FGK=x+41,and m<FGH=180° Find x

Answer 1

Answer: x = -11   ∠FGK = 30°   ∠KGH = 150°

Step-by-step explanation:

∠FGK + ∠KGH = ∠FGH    Segment Addition Postulate

x + 41 + x + 161 = 180       Substitution

2x + 202 = 180                 Simplify (added like terms)

2x = -22                            Subtraction Property of Equality

x = -11                               Division Property of Equality

 

∠FGK = x + 41     = (-11) + 41    = 30

∠KGH = x + 161   = (-11) + 161   = 150