What is the point slope form of the line with slope -3/7 that passes through the point (5, 8)?

ANSWER:
Your answer is the 3rd one: y - 8 = -3/7(x - 5)
ABOUT POINT SLOPE FORM:
ABOUT PROBLEM:
y - Y1 = m (x - X1)
y - 8 = -3/7(x - 5) --- IN POINT SLOPE FORM
Hope this helps you!!! :)
The line with a slope -3/7 and passes through the point (5, 8) has an equation of y - 8 = (-3/7)(x - 5)
The equation of a straight line is given by:
y = mx + b;
where y,x are variables, m is the slope of the line and b is the y intercept.
Since the line has a slope -3/7 and passes through the point (5, 8), the equation of the line is:
[tex]y-y_1=m(x-x_1)\\\\y-8=-\frac{3}{7} (x-5)[/tex]
Hence a line with a slope -3/7 and passes through the point (5, 8) has an equation of y - 8 = (-3/7)(x - 5)
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