Answer:
D
Step-by-step explanation:
given [tex]\frac{j^2}{2j}[/tex] × [tex]\frac{2j}{3g}[/tex]
the 2j on the denominator of the first fraction cancels with the 2j on the numerator of the second fraction, leaving the expression in simplified form as
= [tex]\frac{j^2}{3g}[/tex] → D
