Respuesta :

First question:

By definition of sine and cosine, we have

[tex]\sin30^\circ=\dfrac h{\sqrt5}\implies h=\dfrac{\sqrt5}2[/tex]

[tex]\cos30^\circ=\dfrac g{\sqrt5}\implies g=\dfrac{\sqrt{15}}2[/tex]

Second question:

By definition of tangent, we have

[tex]\tan60^\circ=\dfrac{5\sqrt2}x\implies x=\dfrac{5\sqrt2}{\sqrt3}=\dfrac{5\sqrt6}3[/tex]

Then by Pythagoras' theorem,

[tex](5\sqrt2)^2+x^2=y^2\implies y=\sqrt{(5\sqrt2)^2+\left(\dfrac{5\sqrt6}3\right)^2}=\sqrt{50+\dfrac{50}3}=\sqrt{\dfrac{200}3}=\dfrac{10\sqrt6}3[/tex]

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