Question

Drag each expression to show whether it is equivalent to 8(t+8),8t +8, or neither

Answer 1

Answer:

Box-1:

Neither

Box-2:

$8(t+8)$

Box-3:

$8(t+8)$

Box-4:

$8t+8$

Box-5:

Neither

Box-6:

$8t+8$

Step-by-step explanation:

We can verify each box

Box-1:

$(8+t)+(8+8)$

we can simplify it by combining like terms

$=8+t+8+8$

$=8+t+16$

$=t+24$

none of them matches

so, Neither

Box-2:

$8t+64$

we can write as

$8\times t+8\times 8$

now, we can factor out 8

$8(t+8)$

Box-3:

$8\cdot t+8\cdot 8$

we can factor out 8

$8(t+8)$

Box-4:

$4t+8+4t$

we can combine like terms

$4t+4t+8$

$8t+8$

Box-5:

$8t+16$

we can factor common term

$8\times t+8\times 2$

now, we can factor out 8

$8(t+2)$

so, we can see that none are matching

so, Neither

Box-6:

$4(2t+2)$

we can distribute 4

$4\times 2t+4\times 2$

we can simplify it

$8t+8$

Answer 2

simple answer

8(t+8):

(8 • t) + (8 • 8)

8t + 64.

8t + 8:

4t + 8 + 4t

4(2t + 2)

Neither:

(8 + t) + (8 + 8)

8t + 16

pls mark brainlist