Respuesta :

Answer:  300 m

Step-by-step explanation:

[tex]distance(s)=v_it+\dfrac{1}{2}at^2 \quad \text{where}\ v_i \text{is initial velocity, a is acceleration, t is time}[/tex]

[tex]s=(15)(10)+\dfrac{1}{2}(3)(10)^2[/tex]

  = 150 + 150

  = 300

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