Question

If f(x) = 1 – x, which value is equivalent to |f(i)|?
0
1
√2
√-1

Answer 1

Answer:

$\sqrt{2}$

Step-by-step explanation:

We plug in $i$ into $f(x)$ to get:

$f(i)=1-i$

Here, $i$ is the imaginary number $i=\sqrt{-1}$

To get absolute value of an imaginary number, we use the following formula:

$a+bi=\sqrt{a^2+b^2}$

So absolute value of $f(i)$ is:

$|f(i)|=\sqrt{(1)^2+(1)^2} \\=\sqrt{1+1} \\=\sqrt{2}$