Answer:
Step-by-step explanation:
Sales of the chocolate ice cream is 45%, 30% for strawberry and 25% (100%-45%-30%) of vanilla.
Percentages of cone sales for chocolate, strawberry and vanilla are 75%, 60% and 40%respectively.
A. Probability chocolate chosen: 45%=0.45
B. Probability strawberry chosen: 30%=0.30
C. Probability vanilla chosen:25%=0.25
D. Probability ice cream on a cone: 75%×45%+60%×30%+40%×25%
=0.75×0.45+0.60×0.30+0.40×0.25
=0.3375+0.18+0.1
=0.6175
E. Probability ice cream in a cup: 1- Probability ice cream in a cone
=1-0.6175
=0.3825
Probability that the ice cream sold on a cone and was strawberry flavoured is : 30%×60%
=0.30×0.60
=0.18
Answer: 0.18.
Step-by-step explanation: Let us define the following events
A= event that chocolate chosen,
B=event that strawberry chosen,
C=event that vanilla chosen,
D=event of choosing ice-cream on a cone
and
E=event of choosing ice-cream on a cup.
Then, according to the given information, we have
P(A)=0.45, P(B)=0.30, P(C)=0.25, P(A\D)=0.75, P(B\D)=0.60 and P(C\D)=0.40.
Therefore, the probability that the ice-cream was sold on a cone and was strawberry flavour is given by
[tex]P(B\cap D)=P(B)\times 0.60\\\Rightarrow P(B\cap D)=0.30\times 0.60\\\Rightarrow P(B\cap D)=0.18.[/tex]
Thus, the required probability is 0.18.
