Answer:
Step-by-step explanation:
Another very interesting problem
If the candles were all of a different color, then the first candle (randomly chosen) would be 7. The second candle would be any one of 6. Third would be any one of the remaining 5, then 4 then 3 then 2 then 1
The abbreviated way of writing that is 7! which means that the number of different ways would be
7*6*5*4 *3*2*1
However this problem is not that simple The complexity comes from the fact that there are colors that are duplicated.
That event is handled by dividing 7! /by 3! and another 3!
The result is 140
3! = 3*2*1 = 6
So you would take 7! and divide by 6*6
5040/36 = 140
This problem is much more difficult than any of the others.