Question

47.0 ml of an HBr solution were rotated with 37.5 ml of a 0.215 m lioh solution to reach the equivalent point. What is the molarity of the hbr solution

Answer 1

The molarity of the HBr solution is 0,172 M.

The neutralization reaction between LiOH and HBr is the following:

HBr(aq) + LiOH(aq) → LiBr(aq) + H₂O(l)

Answer 2

Answer:

0.172 mol·L⁻¹

Step-by-step explanation:

1. Write the chemical equation for the reaction.

HBr + LiOH ⟶ LiBr + H₂O

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2. Calculate the moles of LiOH

c = n/V         Multiply each side by V

n = Vc

V = 0.0375 L

c = 0.215 mol·L⁻¹

Moles of LiOH = 0.0375× 0.215

Moles of LiOH = 8.062 × 10⁻³ mol LiOH

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3. Calculate the moles of HBr

1 mol HBr ≡ 1 mol LiOH

Moles of HBr = 8.062 × 10⁻³× 1/1

Moles of HBr = 8.062 × 10⁻³ mol HBr

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4. Calculate the molar concentration of the HBr

V = 47.0 mL = 0.0470 L

c = 8.062 × 10⁻³/0.0470

c = 0.172 mol·L⁻¹