talyricsm49ox6aix
talyricsm49ox6aix talyricsm49ox6aix
  • 29-12-2018
  • Mathematics
contestada

HELP PLEASE! solve for x and y.

HELP PLEASE solve for x and y class=

Respuesta :

wegnerkolmp2741o
wegnerkolmp2741o wegnerkolmp2741o
  • 29-12-2018

Answer:

x=24

y = 8 sqrt(3)

Step-by-step explanation:

Since this is a right triangle, we can use sin and cos

sin 30 = opposite/ hypotenuse

sin 30 = y/ 16 sqrt(3)

Multiply each side by 16 sqrt(3)

16 sqrt(3) * sin 30 = y

16 sqrt(3) * 1/2 = y

8 sqrt(3) = y


cos 30 = adjacent/ hypotenuse

            = x/16 sqrt(3)

Multiply each side by 16 sqrt(3)

16 sqrt(3) cos 30 = x

16 sqrt(3) * (sqrt(3)/2) = x

8 * sqrt(3)*sqrt(3)

8 * 3 = x

24 =x

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