Question

An arithmetic sequence has a first term of 3 and a fifth term of 31. What is the second term?

Answer 1

Answer:

10

Step-by-step explanation:

let's call the difference in each term d so the sequence would look like

3,(3+d),(3+2d),(3+3d),(3+4d)

notice how in this sequence that (3+4d) is the fifth term so it must equal 31

3+4d=31

4d=28

d=7

now plug this into the second term

(3+(7))

and we see that the second term is 10

Answer 2

The value of the second term will be 10.

Since the arithmetic sequence has a first term of 3 and the fifth term of 31, this can be represented thus:

First term = a = 3

Fifth term = a + 4d = 31.

Substitute the value of a into the second equation.

a + 4d = 31

3 + 4d = 31

4d = 31 - 3

4d = 28.

d = 28/4

d = 7

Therefore, the value of the second term will be:

= a + d

= 3 + 7

= 10

The value of the second term will be 10.

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