Respuesta :
Answer:
$29.02
Step-by-step explanation:
We will use compound interest formula to find the amount of interest after 3 months.
[tex]A=P(1+\frac{r}{n})^{nT}[/tex], where,
A= Amount after T years.
P= Principal amount.
r= Annual interest rate in decimal form.
n= Number of times interest is compounded per year.
T= Time in years.
Let us convert our given interest rate in decimal form.
[tex]3.55\%=\frac{3.55}{100}=0.0355[/tex]
Let us convert our given time in years.
[tex]3\text{ months}=\frac{3}{12}\text{ years}=0.25\text{ years}[/tex]
Let us substitute our given values in above formula.
[tex]A=3260(1+\frac{0.0355}{12})^{12\times 0.25}[/tex]
[tex]A=3260(1+0.0029583333333333)^{3}[/tex]
[tex]A=3260(1.0029583333333333)^{3}[/tex]
[tex]A=3260\times 1.0089012810988858948[/tex]
[tex]A=3289.018176382368017048[/tex]
We will use formula [tex]A=P+I[/tex] to find the amount of interest.
[tex]3289.018176382368017=3260+I[/tex]
[tex]3289.018176382368017-3260=I[/tex]
[tex]29.018176382368017=I[/tex]
[tex]I\approx 29.02[/tex]
Therefore, the total interest earned by the end of the third month will be $29.02.
Answer:
$28.59
Step-by-step explanation:
GradPoint doesn't seem to have the correct answer. THe closest I could get was to take 3,260 x .0355 x 90/365 = 28.54