The formula for kinetic energy is KE = (1/2) (mass) (speed²)
== The 50 kg ball traveling at 10 m/s has some kinetic energy.
== A 50 kg ball traveling at 20 m/s would be moving at double the speed. So it would have (2)² = 4 times as much kinetic energy.
== A 50 kg ball traveling at 5 m/s would be moving at 1/2 the speed. So it would have (1/2)² = 1/4 as much kinetic energy.
== A 50 kg person falling at 10 m/s would have exactly the same amount of kinetic energy as the 50 kg ball traveling at 10 m/s.
The kinetic energy in each case will varies as 4 times, 1/4 times and same value as the initial obtained kinetic energy.
Given data:
The mass of ball is, m = 50 kg.
The speed of ball is, v = 10 m/s.
The another value of speed is, v' = 20 m/s.
The third value of speed is, u = 5 m/s.
The fourth value of speed is, u' = 10 m/s.
The standard expression for kinetic energy is given as,
KE = (1/2)mv²
here,
m is the mass and v is the speed of the object.
For 50 kg ball traveling at 10 m/s, the kinetic energy is,
KE = (1/2)(50)(10)²
KE = 2500 J
== A 50 kg ball traveling at 20 m/s would be moving at double the speed. So it would have (2)² = 4 times as much kinetic energy.
== A 50 kg ball traveling at 5 m/s would be moving at 1/2 the speed. So it would have (1/2)² = 1/4 as much kinetic energy.
== A 50 kg person falling at 10 m/s would have exactly the same amount of kinetic energy as the 50 kg ball traveling at 10 m/s.
Thus, we can conclude that the kinetic energy in each case will varies as 4 times, 1/4 times and same value as the initial obtained kinetic energy.
Learn more about the kinetic energy here:
https://brainly.com/question/17858145
