Answer:
The theater is approximately 3.16 units from Sam's location.
Step-by-step explanation:
The distance between points [tex](x_{1}, y_{1})[/tex] and [tex](x_{2}, y_{2})[/tex] is given by:
[tex]d=\sqrt{(x_{2}-x_{1} )^{2}+(y_{2}-y_{1} )^{2} }[/tex]
So, the distance of the theater from Sam's location is:
[tex]d=\sqrt{(-3-(-4) )^{2}+(5-2 )^{2} }[/tex]
[tex]=\sqrt{1^{2}+3^{2} }[/tex]
[tex]=\sqrt{10}[/tex]
= 3.16 approximately
Hence, the theater is approximately 3.16 units from Sam's location.
