Please help! Need answered! Please and thank you.



Answer: (a) 5
Step-by-step explanation:
[tex]\lim_{x \to 2} 5[/tex] means what is the y-value when x = 2 .
The given equation is: y = 5 so the y-value is 5 for all values of x
Answer: (c) 13
Step-by-step explanation:
f(x) = x² + 5x
f'(x) = 2x + 5
f'(4) = 2(4) + 5
= 8 + 5
= 13
Answer: (c) 2
Step-by-step explanation:
The question is asking what the y-value is when x = -2. The graph shows that the coordinate (-2, 2) is on the curve. So, when x = -2, y = 2.
Answer:
lim x→2 5 =5
The slope is 13
lim x→-2 x^2 -2 =2
Step-by-step explanation:
lim x→2 5 =5
The limit of a constant is the constant
f(x) = x^2 +5x
We need to take the derivative
f'(x) = 2x+5
Then evaluate the derivative at x=4 (4,36)
f'(4) = 2*4 +5
= 8+5
= 13
The slope is 13
lim x→-2 x^2 -2 =2
Looking at the graph, the value of the function at -2 is about 2
We can also calculate it (-2)^2 -2 = 4-2 = 2