Need help with #18 ASAP. Will pick brainliest and question worth 20 points.

Answer:
scoops 1 1/2 5 12.8 1.5 1.05 20 12.25
milk 10 5 50 128 15 10.5 200 122.5
Step-by-step explanation:
The problem states 1 scoop per 10 oz of milk
1 scoop x scoops
------------ = ------------
10 oz 5 oz
Using cross products
1 *5 = x * 10
Divide by 10
5/10 =x
1/2 scoops
1 scoop 5 scoops
------------ = ------------
10 oz x oz
Using cross products
1 *x = 5 * 10
x =50
50 oz
1 scoop x scoops
------------ = ------------
10 oz 128 oz
Using cross products
1 *128 = x * 10
Divide by 10
x =128/10
12.8 oz
1 scoop 1.5 scoops
------------ = ------------
10 oz x oz
Using cross products
1 *x = 1.5 * 10
x =15
15 oz
1 scoop x scoops
------------ = ------------
10 oz 10.5 oz
Using cross products
1 *10.5 = x * 10
Divide by 10
x =10.5/10
1.05 oz
scoop 20 scoops
------------ = ------------
10 oz x oz
Using cross products
1 *x = 20 * 10
x =200
200 oz
scoop 12.25 scoops
------------ = ------------
10 oz x oz
Using cross products
1 *x = 12.25 * 10
x =122.5
122.5 oz
Answer:
[tex]\underline {\text{P}\ \ |\quad1\quad| \quad\frac{1}{2}\quad|\quad5\quad|\quad12.8\quad| \quad1.5\quad| \quad1.05\quad|\quad20 \quad|\quad12.25\quad|}\\{\text{M}\ |\quad10\ \ | \quad 5\quad|\quad50\ \ |\quad128.\quad|\quad15\quad| \quad10.5\quad|\quad200\ |\quad122.5\quad|}[/tex]
Step-by-step explanation:
Set up the proportion as [tex]\dfrac{1 \text{ powder}}{10 \text{ milk}}=\dfrac{P}{M}[/tex], then cross multiply and solve for the variable.
Column 1: [tex]\dfrac{1}{10} =\dfrac{1}{M}[/tex] → M = 10
Column 2: [tex]\dfrac{1}{10} =\dfrac{P}{5}[/tex] → 5 = 10P → [tex]\frac{1}{2} = P[/tex]
Column 3: [tex]\dfrac{1}{10} =\dfrac{5}{M}[/tex] → M = 50
Column 4: [tex]\dfrac{1}{10} =\dfrac{P}{128}[/tex] → 128 = 10P → 12.8 = P
Column 5: [tex]\dfrac{1}{10} =\dfrac{1.5}{M}[/tex] → M = 15
Column 6: [tex]\dfrac{1}{10} =\dfrac{P}{10.5}[/tex] → 10.5 = 10P → 1.05 = P
Column 7: [tex]\dfrac{1}{10} =\dfrac{20}{M}[/tex] → M = 200
Column 8: [tex]\dfrac{1}{10} =\dfrac{12.25}{M}[/tex] → M = 122.5