Respuesta :

Answer:

 scoops 1       1/2     5      12.8   1.5    1.05     20    12.25

 milk      10     5       50   128    15     10.5   200    122.5

Step-by-step explanation:

The problem states 1 scoop per 10 oz of milk

1 scoop        x scoops

------------ = ------------

10 oz             5 oz

Using cross products

1 *5 = x * 10

Divide by 10

5/10 =x

1/2 scoops

1 scoop        5 scoops

------------ = ------------

10 oz             x oz

Using cross products

1 *x = 5 * 10

x =50

50 oz

1 scoop        x scoops

------------ = ------------

10 oz             128 oz

Using cross products

1 *128 = x * 10

Divide by 10

x =128/10

12.8 oz

1 scoop        1.5 scoops

------------ = ------------

10 oz             x oz

Using cross products

1 *x = 1.5 * 10

x =15

15 oz

1 scoop        x scoops

------------ = ------------

10 oz             10.5 oz

Using cross products

1 *10.5 = x * 10

Divide by 10

x =10.5/10

1.05 oz

scoop        20 scoops

------------ = ------------

10 oz             x oz

Using cross products

1 *x = 20 * 10

x =200

200 oz

scoop        12.25 scoops

------------ = ------------

10 oz             x oz

Using cross products

1 *x = 12.25 * 10

x =122.5

122.5 oz

Answer:

[tex]\underline {\text{P}\ \ |\quad1\quad| \quad\frac{1}{2}\quad|\quad5\quad|\quad12.8\quad| \quad1.5\quad| \quad1.05\quad|\quad20 \quad|\quad12.25\quad|}\\{\text{M}\ |\quad10\ \ | \quad 5\quad|\quad50\ \ |\quad128.\quad|\quad15\quad| \quad10.5\quad|\quad200\ |\quad122.5\quad|}[/tex]

Step-by-step explanation:

Set up the proportion as [tex]\dfrac{1 \text{ powder}}{10 \text{ milk}}=\dfrac{P}{M}[/tex], then cross multiply and solve for the variable.

Column 1: [tex]\dfrac{1}{10} =\dfrac{1}{M}[/tex] → M = 10

Column 2: [tex]\dfrac{1}{10} =\dfrac{P}{5}[/tex] → 5 = 10P → [tex]\frac{1}{2} = P[/tex]

Column 3: [tex]\dfrac{1}{10} =\dfrac{5}{M}[/tex] → M = 50

Column 4: [tex]\dfrac{1}{10} =\dfrac{P}{128}[/tex] → 128 = 10P  → 12.8 = P

Column 5: [tex]\dfrac{1}{10} =\dfrac{1.5}{M}[/tex] → M = 15

Column 6: [tex]\dfrac{1}{10} =\dfrac{P}{10.5}[/tex] → 10.5 = 10P  → 1.05 = P

Column 7: [tex]\dfrac{1}{10} =\dfrac{20}{M}[/tex] → M = 200

Column 8: [tex]\dfrac{1}{10} =\dfrac{12.25}{M}[/tex] → M = 122.5


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