Question

Simplify 3 square root of 5 end root minus 2 square root of 7 end root plus the square root of 45 end root minus square root of 28
2 square root of 12
2 square root of 2
6 square root of 5 end root minus 4 square root of 7
6 square root of 10 end root minus 4 square root of 14

Answer 1

Answer:

6 square root of 5 end root minus 4 square root of 7

Step-by-step explanation:

$3\sqrt{5}-2\sqrt{7}+\sqrt{45}-\sqrt{28}=3\sqrt{5}-2\sqrt{7}+\sqrt{3^2\cdot 5}-\sqrt{2^2\cdot 7}\\\\=(3+3)\sqrt{5}+(-2-2)\sqrt{7}=6\sqrt{5}-4\sqrt{7}$

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Comment on the answer form

In symbols, parentheses are preferred for grouping:

... 6√(5) -4√7

or

... 6(√5)-4√7

As with your "end root" the grouping symbols are only needed to resolve the ambiguity of what's under the radical.

Answer 2

Answer:

Answer:

6 square root of 5 end root minus 4 square root of 7

Step-by-step explanation:

_____

Comment on the answer form

In symbols, parentheses are preferred for grouping:

... 6√(5) -4√7

or

... 6(√5)-4√7

As with your "end root" the grouping symbols are only needed to resolve the ambiguity of what's under the radical.