Answer: By the slope formula.
Step-by-step explanation:
Given: ABC is a triangle (shown below),
In which A≡(6,8), B≡(2,2) and C≡(8,4)
And, D and E are the mid points of the line segments AB and BC respectively.
Prove: DE║AC and DE = AC/2
Proof:
Since, And, D and E are the mid points of the line segments AB and BC respectively.
Therefore, By mid point theorem,
coordinate of D are [tex](\frac{2+6}{2} , \frac{2+8}{2} ) = (\frac{8}{2} , \frac{10}{2} )= (4,5)[/tex]
Coordinate of E are [tex](\frac{2+8}{2} , \frac{2+4}{2} ) = (\frac{10}{2} , \frac{6}{2} )= (5,3)[/tex]
By the distance formula,
[tex]DE=\sqrt{(5-4)^2+(3-5)^2}=\sqrt{5}[/tex]
[tex]AC=\sqrt{(8-6)^2+(4-8)^2}=2\sqrt{5}[/tex]
By the slope formula,
Slope of AC = [tex]\frac{4-8}{8-6} = \frac{-4}{2} = -2[/tex]
Slope of DE = [tex]\frac{3-5}{5-4} = \frac{-2}{1} = -2[/tex]
Statement Reason
1. The coordinate of D are (4,5) and 1. By the midpoint formula
the coordinate of E are (5,3)
2. The length of DE = √5 2. By the Distance formula
The length AC = 2√5 ⇒ Segment DE
is half the length of segment AC
3. The slope of DE = -2 and the 3. By the slope formula
slope of AC = -2
4. DE║AC 4. Slopes of parallel lines are equal