Answer:
See below
Step-by-step explanation:
If |x| < |y| and both are negative the x will be to the right of y on the number line. The point x is loser to the zero on the number line. We can illustrate this by supposing x = -3 and y = -6.
|x| = 3 and |y| = 6 and 3 < 6 but -3 on the number line is higher ( to the right) of -6 and closer to the zero.
|-8 1/3| = 8 1/3
|7 2/3| = 7 2/3
The absolute values of 8 1/3 > than absolute value of 7 2/3. The point 7 2/3 is closer to the zero on a number line.
The absolute value of F is greater than absolute value of E so E is closer to the zero line than F.
