Sound level at distance of 15 m is given as 20 dB
so intensity at this distance is given as
[tex]L = 10 Log\frac{I}{I_0}[/tex]
[tex]20 = 10 Log{I}{10^{-12}}[/tex]
[tex]I_1 = 10^{-10}W/m^2[/tex]
now if we move closer to some some distance the sound level is now 50 dB
now the intensity is given as
[tex]L = 10 Log\frac{I}{I_0}[/tex]
[tex]50 = 10Log\frac{I}{10^{-12}}[/tex]
[tex]I_2 = 10^{-7}W/m^2[/tex]
now we know that
[tex]\frac{I_1}{I_2} = \frac{r_2^2}{r_1^2}[/tex]
[tex]\frac{10^{-10}}{10^{-7}} = \frac{r_2^2}{15^2}[/tex]
[tex]r_2 = 47 cm[/tex]
so now the distance from friend must be 47 cm