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A spinning disc rotating at 130 rev/min slows and stops 31 s later. how many revolutions did the disc make during this time?

Respuesta :

f = 130 revs/min = 130/60 revs/s = 13/6 revs/s
t = 31s
wi = 2πf = 2π × 13/6 = 13π/3 rads/s
wf = 0 rads/s = wi + at
a = -wi/t = -13π/3 × 1/31 = -13π/93 rads/s²
wf² - wi² = 2a∅
-169π²/9 rads²/s² = 2 × -13π/93 rads/s² × ∅
∅ = 1209π/18 rads
n = ∅/2π = (1209π/18)/(2π) = 1209/36 ≈ 33.5833 revolutions.

A spinning disk with 130 rev/min will make 33.5833 revolutions in 31 seconds.

Initial angular velocity,

wi = 2π. f

Where, f - frequency = 130 rev/min = 13/6 rev/s

Thus,

wi = 2π × 13/6

wi = 13π/3 rads/s

Final  angular velocity,

wf = 0 rads/s = wi + at

From acceleration,

a = -wi/t

Where,

a - acceleration

t - time = 31s

So,

t = -13π/3 × 1/31

t = -13π/93 rads/s²

From relation between Tangential velocity and Angular velocity,

wf² - wi² = 2a∅

Where, is the Tangential velocity

Thus,

-169π²/9 rads²/s² = 2 × -13π/93 rads/s² × ∅

∅ = 1209π/18 rads

Thus, the the number of rotations,

n = ∅/2π

n = (1209π/18)/(2π)

n = 1209/36

n  = ≈ 33.5833 revolutions.

Therefore, the disc make 33.5833 revolutions in 31 seconds.

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