Respuesta :

Answer:

x = 2.696, x = -0.696

Step-by-step explanation:

We are given the following function of x and we are to find the zeros for the given quadratic function:

[tex]f(x)= 8x^2-16x-15[/tex]

To find its zeros, we will use the quadratic formula:

[tex]x=\frac{-b+-\sqrt{b^2-4ac} }{2a}[/tex]

Substituting the values in the formula where [tex]a=8[/tex], [tex]b=-16[/tex] and [tex]c=-15[/tex].

[tex]x=\frac{-(-16)+-\sqrt{(-16)^2-4(8)(-15)} }{2(8)}[/tex]

[tex]x=\frac{16+-\sqrt{736} }{16}[/tex]

[tex]x=\frac{16+27.13}{16}[/tex] , [tex]x=\frac{16-27.13}{16}[/tex]

[tex]x = 2.696[/tex] , [tex]x=-0.696[/tex]

Therefore, the solutions are 2.696 and -0.696.

Answer: c on edge

Step-by-step explanation:

x=1-square root 23/8 and x=1+square root 7

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