Question

Which expression below gives the average rate of change of the function g(x) = -x2 - 4x on the interval 6 ≤ x ≤ 8 ?
plsss

Answer 1

Answer:

the first selection (see below)

Step-by-step explanation:

The average rate of change (m) on the interval [x1, x2] is given by ...

... m = (g(x2) -g(x1))/(x2 -x1)

For g(x) = -x²-4x and (x1, x2) = (6, 8), the expression is the one attached.

Answer 2

Answer:

$\frac{[-8^2 - 4(8)]- [-6^2 - 4(6)]}{8-6}$

Step-by-step explanation:

average rate of change of the function g(x) = -x^2 - 4x on the interval 6 ≤ x ≤ 8

To find average rate of change we use formula

Average =$\frac{g(x_2)-g(x_1)}{x^2-x_1}$

use the given interval 6<=-x<=8

x2=8  and x1= 6

we replace the value in the given formula

g(x) = -x^2 - 4x

$g(8) = -8^2 - 4(8)$

$g(6) = -6^2 - 4(6)$

x2-x1 is 8-6

So equation becomes

$\frac{[-8^2 - 4(8)]- [-6^2 - 4(6)]}{8-6}$