8 am to 10:30 am is 2.50 hours.
Old Steamy is going 6.14 mph for 2.5 hours so travels : 6.14 * 2.5 = 15.35 miles.
This means Chug a lug has to travel 290 - 15.35 = 274.65 miles in 2.5 hours.
The speed would be 274.65 / 2.5 = 109.86 miles per hour.
Answer:
The speed of Old Steamy train = 6.14 mph
Train started at 8 a.m. and arrived at 10.30 a.m, this becomes 2.5 hours.
So, distance traveled by Old Steamy train = [tex]Speed\times time[/tex]
=> [tex]6.14\times2.5=15.35[/tex] miles
Now we get that Chug-a-Lug was 290 miles behind the Old steamy.
To know the distance traveled by Chug-a-Lug, we will add distance traveled by Old Steamy to the station plus the distance between the trains.
So, distance traveled by Chug-a-Lug = [tex]15.35+290=305.35[/tex] miles
The speed of Chug-a-Lug =[tex]\frac{Distance}{Time}[/tex]
= [tex]\frac{305.35}{2.5}=122.14[/tex] mph
