Answer:
The correct answer is option A.
Explanation:
A pure water has pH value of 7 which neutral in nature. Pure water equal amount of hydronium ions and hydroxide ions.
[tex]H_2O+H_2O\rightleftharpoons H_3O^++OH^-[/tex]
Ionic product of water = [tex]K_w=1\times 10^{-14}[/tex]
[tex][H_3O^+]=[OH^-][/tex]
[tex]K_w=1\times 10^{-14}=[H_3O^+]\times [OH^-][/tex]
[tex][H_3O^+]=10^{-7}[/tex]
The pH value of pure water :
[tex]pH=-\log[H_3O^+]=-\log[10^{-7}] = 7[/tex]