Respuesta :
QUESTION 1a
We want to find the value of [tex]x[/tex] in the proportion,
[tex]6:9=x:72[/tex]
We rewrite the ratio on each side of the equation as fractions to obtain,
[tex]\frac{6}{9}=\frac{x}{72}[/tex]
We now multiply both sides of the equation by [tex]72[/tex] to get,
[tex]\frac{6}{9}\times 72=\frac{x}{72}\times 72[/tex]
This simplifies to
[tex]\frac{6}{1}\times 8=\frac{x}{1}\times 1[/tex]
[tex]\therefore 48=x[/tex]
[tex]x=48[/tex]
QUESTION 1b
The given proportion is,
[tex]\frac{8}{3}=\frac{40}{x}[/tex]
We cross multiply to obtain,
[tex]8x=3\times 40[/tex]
We divide both sides by 8 to get,
[tex]x=\frac{3\times 40}{8}[/tex]
[tex]\Rightarrow x=\frac{3\times 40}{8}[/tex]
[tex]\Rightarrow x=\frac{3\times 5}{1}[/tex]
[tex]\therefore x=15[/tex]
QUESTION 1c
The given proportion is
[tex]\frac{x}{55}=\frac{3}{5}[/tex]
We multiply both sides by 55 to get,
[tex]\frac{x}{55}\times 55=\frac{3}{5}\times 55[/tex]
This simplifies to
[tex]x=\frac{3}{1}\times 11[/tex]
[tex]\therefore x=33[/tex]
QUESTION 1d
The given proportion is,
[tex]\frac{33}{x}=\frac{11}{5}[/tex]
We cross multiply to get,
[tex]33\times 5=11x[/tex]
We now divide both sides by 11 to get,
[tex]\frac{33\times 5}{11}=x[/tex]
[tex]\Rightarrow x=15[/tex]
QUESTION 2
Since the recipe calls for 5 cups of flour for every 6 teaspoons of salt, we can write the ratio,
[tex]5:6[/tex]
Let a larger recipe of 15 cups of flour correspond to [tex]x[/tex] teaspoons of salt,
Then the proportion becomes,
[tex]5:6=15:x[/tex]
This implies that,
[tex]\frac{5}{6}=\frac{15}{x}[/tex].
We cross multiply to get,
[tex]5x=6\times 15[/tex]
We divide through by 5 to get,
[tex]x=\frac{6\times 15}{5}[/tex]
[tex]\therefore x=18[/tex]
Hence you will need 18 teaspoons of salt.
QUESTION 3
We were given that a 20-foot flagpole casts a 6-foot shadow.
We write this as a ratio to get,
[tex]20:6[/tex]
Let the nearby 30-foot building cast an x-foot shadow.
We can also write this as a ratio to get,
[tex]30:x[/tex]
The proportion now becomes,
[tex]20:6=30:x[/tex]
We cross multiply to get,
[tex]20x=6\times 30[/tex]
This implies that
[tex]x=\frac{6\times 30}{20}[/tex]
[tex]\Rightarrow x=9[/tex]
QUESTION 4
If 15 corresponds to 4, we write the ratio,
[tex]15:4[/tex]
We want to find what number of ads corresponds to 300 columns. Let that number be x.
Then we have the ratio,
[tex]300:x[/tex]
The proportion is
[tex]15:4=300:x[/tex]
This implies that,
[tex]15x=300\times 4[/tex]
[tex]x=\frac{300\times 4}{15}[/tex]
[tex]x=80[/tex]
It must have 80 ads.
QUESTION 5
The given ratio is [tex]5:2[/tex],
Let the gallons of blue paint be [tex]x[/tex]
We can write the ratio [tex]x:8[/tex]
The required proportion is
[tex]5:2=x:8[/tex]
This implies that,
[tex]\frac{5}{2}=\frac{x}{8}[/tex]
We multiply both sides by 8
[tex]x=\frac{5}{2}\times 8[/tex]
[tex]x=20[/tex]
8 gallons of blue paint is needed
