sophiagmoser
sophiagmoser sophiagmoser
  • 20-12-2018
  • Mathematics
contestada

5x^2-(3xy-7x^2)+(5xy-12x^2)
When x=-0.25, and y=4

Respuesta :

Аноним Аноним
  • 20-12-2018

[tex]5x^2-(3xy-7x^2)+(5xy-12x^2)=5x^2-3xy+7x^2+5xy-12x^2=2xy\\\\ 2\cdot(-0.25)\cdot4=-2[/tex]

Answer Link
OlivierGO2005
OlivierGO2005 OlivierGO2005
  • 07-05-2019

Answer:

-2

Step-by-step explanation:

5x^2-(3xy-7x^2)+(5xy-12x^2)

5x^2-3xy+7x^2+5xy-12x^2

[(5x^2+7x^2-12x^2)=0]

-3xy+5xy= -3(-.25)(4)+5(-.25)(4)

-3(-.25)(4)+5(-.25)(4)= 3-5= -2

-2

Answer Link

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