Question

How much current is in a circuit that includes a 9.0 volt battery and a bulb woth a resistance of 4.0 ohms

Answer 1

According to Ohm's law for a portion of the circuit we have:

U=RI=>I=U/R=9/4=2.25 A

Answer 2

Answer:

Current in the circuit, I = 2.25 A

Explanation:

Given that,

Voltage of the battery, V = 9 V

Resistance of the bulb, R = 4 ohms

We need to find the current in the circuit. It can be calculated using Ohm's law. Ohm's law gives the relationship between the current, resistance and the voltage as :

$V=IR$

$I=\dfrac{V}{R}$

$I=\dfrac{9\ V}{4\ \Omega}$

I = 2.25 A

So, the current flowing in the circuit is 2.25 amperes. Hence, this is the required solution.