Question

A jar containing only nickels and dimes contains a total of 60 coins. The value of all the coins in the jar is $4.45. Solve by elimination to find the number of nickels and dimes that are in the jar.

Answer 1

Answer: 31 nickels and 29 dimes

Step-by-step explanation:

Nickels (.05): x

Dimes (.10): y

 Value:     .05x + .10y = 4.45 →  -20(.05x + .10y = 4.45)   →   -x - 2y = -89

Quantity:        x  +    y  = 60   →       1(x  +    y  = 60)           →   x  + y = 60

                                                                                                       -y  = -29

                                                                                                        y  =  29

Next, substitute "29" for "y" into either equation and solve for "x":

x +  y  = 60

x + 29 = 60

x          = 31

Answer 2

The number of nickels and dimes that are in the jar is 31 and 29 respectively.

Given that,

• A jar containing only nickels and dimes contains a total of 60 coins.
• The value of all the coins in the jar is $4.45.
• 1 nickle be 5 cents and 1 dime is 10 cents. Also we assume nickels be x and dimes be y.

Based on the above information, the calculation is as follows:

x + y = 60 ........(1)

5x + 10y = 445.......(2)

Here we multiply by 5 in equation 1

5x + 5y = 300

5x + 10y = 445

-5y = 145

y = 29

So, x = 60 - 29

= 31

Therefore we can conclude that the number of nickels and dimes that are in the jar is 31 and 29 respectively.

Learn more: brainly.com/question/13549064