Can someone please help me with these problems I don't know how to do them. Thank you
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[tex] \bold{FOR \: 1st \: image }[/tex]
By straight line angles property,
▶60 + 4x +20 =180
▶80 +4x =180
▶4x = 180 -80
▶4x = 100
x = 25
So, Second angle
▶4 ×25 +20
▶100 + 20
▶120
[tex] \bold{FOR \: 2nd \: image }[/tex]
3x + x =116
4x=116
x = 29
other angle = 3 ×29
=87
[tex] \bold{FOR \: 3rd \: image }[/tex]
ANGLE CAB + ANGLE ACB = 90
2x + x + 30 =90
3x + 30 =90
3x = 90 - 30
3x= 60
x=20
So, angle CAB = 2 ×20 = 40