someone help pls need help on this one
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Answer:
[tex]\dfrac{2}{3x^5y}[/tex]
Step-by-step explanation:
A negative exponent in the numerator is the same as a positive exponent in the denominator, and vice versa.
... a^-b = 1/a^b . . . . . for any value of b, positive or negative
The exponent of a product is the sum of the exponents:
... (a^b)(a^c) = a^(b+c)
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Applying these rules, you have
... = 2/(3x^4·x·y) = 2/(3x^(4+1)·y) = 2/(3x^5·y)