Answer:
Length of wire = 50 ft
Step-by-step explanation:
In the figure below AB is the telephone pole and C is the point on the ground where wire is anchored.
so we have
AB= 45 ft
∠ACB= 64°
Let is assume the length of the wire be x ft
now in Δ ABC
[tex]sin C = \frac{AB}{AC}[/tex]
we can plug AB= 45, ∠C= 64°and AC=x
so we have
[tex]sin(64)[/tex]°[tex]=\frac{45}{x}[/tex]
[tex]xsin(64)[/tex]°[tex]=45[/tex]
[tex]x=\frac{45}{sin(64)}[/tex]
now we have sin 64°=0.8988
[tex]x=\frac{45}{0.8988}[/tex]
[tex]x=50.07[/tex] ft
rounding to nearest foot
x= 50 ft