Respuesta :

Answer:

[tex]x=3-\sqrt{6},x=3+\sqrt{6}[/tex]

Step-by-step explanation:

we are given equation as

[tex]2x^2-12x=-6[/tex]

Since, we have to solve it by using complete square

so, firstly we will complete square

and then we can solve for x

step-1:

Factor 2 from both sides

[tex]2(x^2-6x)=-3\times 2[/tex]

step-2:

Simplify it

[tex]x^2-6x=-3[/tex]

step-3:

Add both sides 3^2

[tex]x^2-6x+3^2=-3+3^2[/tex]

now, we can complete square

[tex](x-3)^2=6[/tex]

step-4:

Take sqrt both sides

[tex](x-3)=-\sqrt{6},(x-3)=\sqrt{6}[/tex]

step-5:

Add both sides by 3

we get

[tex]x=3-\sqrt{6},x=3+\sqrt{6}[/tex]


Answer:

person above me is correct

Step-by-step explanation:

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