Respuesta :

Answer: A

Step-by-step explanation:

[tex]\overline{AB}[/tex] has a length of 6

[tex]\overline{A'B'}[/tex] has a length of 6 + 12 = 18, which is 3 times the length of [tex]\overline{AB}[/tex]

B = B' so this will be the center point

⇒ center B and a scale factor of 3



Answer:

Option A is the answer.

Step-by-step explanation:

Triangle A'B'C' is a dilation of triangle ABC.

We can apply the formula to get the scale factor as

Scale factor = [tex]\frac{\text{One side of triangle A'B'C'}}{\text{Corresponding side of triangle ABC}}[/tex]

= [tex]\frac{A'B'}{AB}[/tex]

= [tex]\frac{AB'+AA'}{AB}[/tex]

= [tex]\frac{6+12}{6}[/tex]

= [tex]\frac{18}{6}[/tex]

= 3

Therefore, ΔABC has been dilated with a scale factor of 3 about the point B as the center.

Option A is the answer.

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