Catilous Catilous

19-12-2018
Mathematics

contestada

Factor the expression using the GCF.
21a squared b to the 5th power + 49a to the 4th power b cubed

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27-12-2018

[tex]21a^2b^5+49a^4b^3=(7a^2b^3)(3b^2)+(7a^2b^3)(7a^2)=7a^2b^3(3b^2+7a^2)[/tex]

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