TheMeThatMees TheMeThatMees

19-12-2018
Mathematics

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You launch a ball at an angle of 35 degrees above the horizontal with an initial velocity of 38 m/s. What is the time the ball will stay in the air? [Must show work]

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alexyapur0 alexyapur0

19-12-2018

Answer:

t= 2.22 seconds.

Step-by-step explanation:

1) You need to find the vertical velocity.

38*sin(35) = 21.7959

2) You need to use the t=v1y/a formula to find the time to get to the top.

v1y= the vertical velocity, 21.7959

a= Acceleration, 9.8

t=21.7959/9.8

t=2.22

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