Question

how many moles of 02 can be prepared from 6.75 moles of KCIO3 ?

Answer 1

The equation for this question could be $2KClO_{3}$→$2KCl+3O_{2}$ .

so for 6.75 moles of $KClO_{3}$  *3 moles of O_{2}/2 moles of $KClO_{3}$

= 10.125